philips: Philips B2X85U electrolytics replacement

I am restoring a radio Philips B2X85U (or B2K85U). I've got the schematics but I can not realize where to connect the 2 new capacitors in the place of the original can.

I mean, I have 2 capacitors with 4 leads and the PCB of the radio has 5 connection points on the original can.

I guess that the  2 negatives leads have a rail for both of them. Still, I have 4 connection for the other two positive leads.

There is a divider resistor that can solve one lead in two connections but the other positive lead will have to go to the other two connection points?

The pictures will show it.

What I need to know is where I can solder the 4 new leads?

Thanks,

Alvaro Georg 

YouTube: Rádios Antigos & Cia Ltda

Brazil

 

Attachments:

• Model (67 KB)
• Picture (52 KB)
• PCB 1 (73 KB)
• PCB 2 (64 KB)
• Schematics (45 KB)
• Picture 2 (42 KB)

To thank the Author because you find the post helpful or well done.

Hello Alvaro,

 

the two old electrolytic capacitors are built in together in the aluminium case with common ground. The ground connections are the edges of the "triangle".  So it is necessary to connect these three pins together, and to solder both negative pins from the new capacitors to this bridge. The remaining pins at the pcb are the positive connections for your two spare part capacitors.

Hope, i could help you and my english was not too bad...

Michael

To thank the Author because you find the post helpful or well done.

Many thanks Michael, you are 100% correct.

Now that I took out the can (it was a little difficult to make the proper desoldering), it is clear your explanation.

Alvaro.

Attachments:

• can (59 KB)
• can (59 KB)

To thank the Author because you find the post helpful or well done.

Resolution.

Thanks again.

Alvaro.

YouTube Channel: Rádios Antigos & Cia Ltda

Attachments:

• Bridge (61 KB)
• Caps (58 KB)

To thank the Author because you find the post helpful or well done.